y=-1/8x^2+2

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Solution for y=-1/8x^2+2 equation: 


x in (-oo:+oo)

y = (-1/8)*x^2+2 // - (-1/8)*x^2+2

y-((-1/8)*x^2)-2 = 0

(1/8)*x^2+y-2 = 0

1/8*x^2 = -(y-2) // : 1/8

x^2 = 8*(2-y)

x^2 = 8*(2-y) // ^ 1/2

abs(x) = 2*2^(1/2)*(2-y)^(1/2)

x = 2*2^(1/2)*(2-y)^(1/2) or x = -(2*2^(1/2)*(2-y)^(1/2))

x in { 2*2^(1/2)*(2-y)^(1/2), -(2*2^(1/2)*(2-y)^(1/2)) }

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